So my math teacher gave us some extra credit. The problem is this:
x^3 - 1 = 0
x^6 - 1 = 0
x^12 - 1 = 0
Solve for all (real and imaginary) values of x
I promptly factored/solved them and showed him my answers. He said, "What you did is correct, but this can also involve trigonometry and there should be a picture involved." So I need to show him that to get the extra credit.
The answers to the first one (x^3 - 1 = 0) are this btw, if it helps:
x = {1, (-1/2) + (sqrt(3)/2)i, (-1/2) - (sqrt(3)/2)i }
Any help is much appreciated, as I have no idea what he's going on about.